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364 solutions

Gibbs Free Energy

Q. Consider the reaction: Cgraphite(s) + O2(g) ΔG° = -400 kJ Which of the following is a possible value K for this reaction? a) 10^-70 b) 10^70 c) -0.56 d) 0.56

Solved • Feb 5, 2020

Gibbs Free Energy

Q. Calculate the equilibrium constant at 25°C for a reaction for which ΔG° = -4.22 kcal/mol. a) 1240.51 b) -1240.51 c) 2484.02 d) 620.254

Solved • Feb 5, 2020

Gibbs Free Energy

Q. Consider the following reaction at 25.0 °C. 2NO2(g) ⇌ N2O4(g) The values of ΔH° and ΔS° are -58.03 kJ/mol and -176.6 J/K•mol, respectively. Calculate the value of K at 25.0 °C. Assuming ΔH° and ΔS° are temperature independent, estimate the value of K at 100 °C.

Solved • Feb 2, 2020

Gibbs Free Energy

Q. At constant Tand P, any reaction will be spontaneous if . a.∆G> 0. d.∆S< 0. b.∆G< 0. e.∆H< 0. c.∆S> 0.

Solved • Jan 23, 2020

Gibbs Free Energy

Q. Calculatethe standard free energy change for the reaction 2 SO3(g)-->2 SO2(g) + O2(g)at 800.0 °C given the following information: ΔHf° (kJ/mol): SO3(g): -395.7 SO2(g): -296.8 S° (J / mol •K): SO3(g): 256.8 SO2(g): 248.2 O2(g): 205.0 a.−3.70 kJ d.+348.0 kJ b.+47.6 kJ e.+399.3 kJ c.−399.3 kJ

Solved • Jan 23, 2020

Gibbs Free Energy

Q. 6CO2(g) + 6H2O(l) → C6H12O6 + 6O2(g) ΔH°= 2800.8 kj and ΔS° = -259.0 J/K The standard free energy change for the reaction of 1.98 moles of CO2(g) at 250 K, 1 atm would be ____ kJ. This reaction is (reactant, product) ____ favored under standard conditions at 250 K. Assume that ΔH° and ΔS° are independent of temperature.

Solved • Jan 22, 2020

Gibbs Free Energy

Q. H2(g) + C2H4(g) → C2H6(g) Using standard thermodynamic data at 298K, calculate the free energy change when 1.930 moles of H2(g) react at standard conditions.

Solved • Jan 22, 2020