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Empirical Formula

Q. The analysis of a compound gives the following percent composition by mass: C: 61.59 percent; H: 9.427 percent; S: 9.675; O: 19.31 percent. What is its molecular formula given that its molar mass is 331.5 g?

Solved • May 4, 2020

Empirical Formula

Q. The analysis of a compound gives the following percent composition by mass: C: 62.49 percent; H: 11.47 percent; S: 10.43 percent; O: 15.61 percent. What is its molecular formula given that its molar mass is 307.5?

Solved • May 2, 2020

Empirical Formula

Q. an unknown compound was found to have a percent composition as follow : 47.0%pottassium, 14.5%carbon , and 38.5%oxygen. if the true molar mass of the compound is 166.2g/mol, what is the molecular formula?

Solved • Nov 25, 2019

Empirical Formula

Q. Determine the empirical formula for a compound that contains 58.8 % C, 9.8 % H, and 31.4 % S by mass.

Solved • Apr 3, 2020

Empirical Formula

Q. Measurements show that unknown compound X has the following composition: Elements mass% calcium 38.7% phosphorus 19.9% oxygen 41.2% Write the empirical formula of X.

Solved • Mar 26, 2020

Empirical Formula

Q. A small coil of magnesium ribbon is placed in a crucible. The crucible cover have a mass of 21.35 grams. Measuring the mass, including the magnesium, gives 21.63 grams. The crucible, cover and contents are heated and then cooled and treated with water. A second heating and measuring of the final product (magnesium combined with oxygen) gives a mass of 21.82 grams. Determine the empirical formula of this oxide of magnesium.

Solved • Mar 24, 2020

Empirical Formula

Q. Two elements, A and B, combine to form two binary compounds. In the first compound, 13.23g of A combines with 2.83g of B. Inthe second compound, 5.07g of A combines with 3.25g of B. If the formula of the second compound is AB, what is the possible formula of the first compound?

Solved • Mar 12, 2020