H2(g)+I2(g)⇌2HI(g) Reaction mixture @ equilibrium @ 175 K contains PH2=0.958atm, PI2=0.877atm, & PHI=0.020atm. A second reaction mixture, also @ 175 K contains PH2=PI2= 0.628 atm , & PHI= 0.108 atm

what will be the partial pressure of HI when the reaction reaches equilibrium at 175 K?

I keep getting the answer of 0.014 atm but it keeps counting me wrong saying its close but not quite right.