What pressure is needed to confine an ideal gas to 65.0 L after it has expanded from 34.0 L and 2.6 atm at constant temperature?

asked by @cadel3 • 11 months ago • Chemistry • 5 pts
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1 answer

Hey Cadel! You'll have to use Boyle's law, P1V1=P2V2 to solve for the pressure. Since it expands, you can immediately expect a lower pressure.

P1 = 2.6 atm

V1 =34.0 L

P2 =?

V2 = 65.0 L

P1V1=P2V2

(2.6 atm)(34.0 L)=(P2)(65.0 L)

P2 = (2.6 atm)(34.0 L)/(65.0 L) = 1.36 atm

I hope this helps!

answered by @leot1 • 11 months ago