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Calculate the voltage of the cell Ag(s) | AgBr (s), NaBr (aq, 1.0M) || CdCl2 (aq, 0.050 M) | Cd (s) AgBr (s) + e-  Ag (s) + Br - E° = 0.071 V Ag+ + e-  Ag (s) E° = 0.799 V Cd2+ + 2e-  Cd (s) E° = -0.402 V Ksp (AgBr(s) ) = 5.0 x 10-13