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What will be the pH of a buffer solution prepared from 0.20 mol NH3, 0.40 mol NH4NO3, and just enough water to give 1.00 L of solution? (Kb = 1.76 x 10-5) --I worked this out and got 8.96 as the pH, but I have seen other sources that got another answer. I need steps and explanations if possible because I am confused!