I got this question wrong on my test and I would like to know how to solve it: Potassium (k) has an atomic mass of 39.0983 amu and only two naturally occurring isotopes. The K-41 isotope (40.9618 amu

asked by @claritas1 • 11 months ago • Chemistry • 5 pts

) has an natural abundance of 6.7302% What is the mass (in amu) of the other isotope?

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1 answer

if 1 is 6.7302%=0.067302 2nd is 100%-6.7302%=93,2698% =0.932698 (I am not going to count sig. figs.) 0.067302*40.9618+0.932698x=39.0983. Solve for X. X=38.9630423 amu

answered by @nikaa18 • 11 months ago