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Using the following thermochemical data: 2Ho (s) + 6HF (g) → 2HoF3 (s) + 3H2 (g) ∆rH° = -1787.4 kJ/mol-rxn 2Ho (s) + 6HCl (g) → 2HoCl3 (s) + 3H2 (g) ∆rH° = -1457.0 kJ/mol-rxn calculate ∆rH°, for the following reaction: HoF3(s) + 3HCl (g) → HoCl3 (s) + 3HF (g)