Hi there! According to the spectra, there will be 4 unique signals for the molecule. A singlet, triplet, quintet and another triplet. That singlet represents the H of C1 and C5, quintet is that Hs at the C2-. Terminal Hs of -CH3 and that H at C3 where -OH is attached are triplets. Your molecule will have a signal of a sextet from that H at C2 so we can dismiss that molecule. This type of problem requires us to be creative and draw more structures that fits on the signals. Keep on practicing and you'll be better in solving NMR problems. Hope that makes sense!