The esterification of acetic acid and ethanol is given by the reaction below:
C2H5OH(aq) + CH3COOH(aq) ⇌ CH3COOC2H5(aq) + H2O(l)
When 1.00 mol of ethanol was mixed with 2.00 mol of acid in a 1.00 L flask, 0.86 mol of ester was formed at room temperature. What is the value of the equilibrium constant, Kc?
A) 2.3 B) 4.6 C) 5.4 D) 0.43