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The esterification of acetic acid and ethanol is given by the reaction below: C2H5OH(aq) + CH3COOH(aq) ⇌ CH3COOC2H5(aq) + H2O(l) When 1.00 mol of ethanol was mixed with 2.00 mol of acid in a 1.00 L flask, 0.86 mol of ester was formed at room temperature. What is the value of the equilibrium constant, Kc? A) 2.3 B) 4.6 C) 5.4 D) 0.43