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Write the equilibrium equation for the reverse reaction: 2 CH4(g) + 3 O2(g) = 2 CO(g) + 4 H2O(g) A) Kp' = [PCO]2 [PH2O]4 / [PCH4]2 [PO2]3 B) Kp' = [PCH4]2 [PO2]3 / [PCO]2 [PH2O]4 C) Kp' = 2[PCO] + 4[PH2O] / 2[PCH4] + 3[PO2] D) Kp' = 2[PCH4] + 3[PO2] / 2[PCO] 4[PH2O]