A certain reaction has an activation energy of 64.58 kJ/mol. At what Kelvin temperature will the reaction proceed 4.00 times faster than it did at 309 K?

asked by @amandac86 • about 1 year ago • Chemistry • 5 pts

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3 answers

You can use this relation derived from the Arrhenius equation. I've uploaded the complete solution below. We can just use 1/4 as the ration of k1 and k2 since it is given that it should be 4 times faster. I hope this makes sense! enter image description here

answered by @leot1 • about 1 year ago

T= 327.035k

answered by @mardiaw1 • about 1 year ago

T= 327.035k

answered by @clarem11 • about 1 year ago