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Calculate [d]Hrxn for 2NOcl9g)---N2(g) + 02(g) + Cl2(g) Given the following set of reactions: 1/2 N2(g)+1/2 O2(g) --NO(g) [d}Hrxn = 90.3 kJ NO(g) + 1/2 Cl2(g) ---NOCl(g) [d]Hrxn - 38.6 Kj