asked by @alibethh1 •
11 months ago •
Chemistry
• 5 pts

e is only 34% as strong as the pressure at sea level?

Hey there. Ok so for this question we are dealing with pressure, temperature and vaporization so that means we need to use the Clausius-Clapeyron Equation:

ln (P2/P1) = - delta Hvaporization/R x [(1/T2) - (1/T1)]

At 100 degrees Celsius we are dealing with normal pressure which is 760 mmHg or torr.

34% of 760 is 0.34 x 760 = 258.4

ln (258.4 torr/760 torr) =[ -44,010 J/mol / 8.314 J/mol x K] x [(1/T2) - (1/373.15 K)]

-1.07881 = -5293.48 x [(1/T2) - (1/373.15 K)]

0.000204 = [(1/T2) - (1/373.15 K)]

0.002884 = 1/T2

T2 = 346.8 K

Hope that helps.

answered by @jules •
11 months ago

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