The activation energy for a given reaction is 56 kJ/mol. At what temperature would the rate constant be quadruple what is was at 273K?

asked by @jadec9 • about 1 year ago • Chemistry • 5 pts

Can someone show me step by step how to solve this? Thank you!

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1 answer

Hey Jade! Here is the solution to your problem. Notice that they want you to understand that the second rate constant K (K2) will have 4 times the rate of K1. Here, we know that the ratio will be 4:1, so we just plug in a 1 for K1 and a 4 for K2.

Also, you are given the first temperature T1, given to be 273 K. The problem asks you to solve for the second temperature T2. You are given the activation energy value and R is a constant, so you have everything to solve for the missing T2.

Make sure to convert the 56 kJ/mol from the activation energy to J, since your R constant has joules and you want those units to cancel out. Everything else is just plugging in and solving.

Hope this helps! Please let us know if you have any other questions, comments, or concerns :)

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answered by @sabrina • about 1 year ago
  • thank you!! Jade commented about 1 year ago
  • No problem! :) Sabrina commented about 1 year ago