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HgO(s) → Hg(l) + 1/2 O2(g), ΔH° = 90.84 kJ/mol. Estimate the temperature this reaction will become spontaneous. S°(Hg) = 76.02 J/K • mol, S°(O2) = 205.0 J/K • mol, S°(HgO) = 70.29 J/K • mol.