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The decomposition of barium nitrate is given by: Ba(NO3)2(s) ⇌ BaO(s) + 2NO2(g) + ½ O2(g). At 25°C, ∆H° = 504.7 kJ/mol and ∆S° = 438.9 J/(mol∙K). Caclulate the equilirium constant Keq at the given T.