Hi Christopher! This reaction is an epoxidation followed by an acid catalyzed ring opening which results an anti-addition configuration for the -OH groups. We need to have one of the -OH group in this sample to be in the equatorial while the other needs to be in the axial. Answer for this will be B because both II and IV showed an anti configuration of the -OH groups. You can watch Johnny's video on Epoxide Ring Opening here: https://www.clutchprep.com/organic-chemistry/epoxide-ring-opening-2/?c_id=2643
Hope that helps!