A volume of 38.2 mL of a 0.468 M Ca(NO3)2 solution is mixed with 75.5 mL of a 1.696 M Ca(NO3)2 solution. Calculate the concentration of the final solution.

asked by @imeldas1 • over 1 year ago • Chemistry • 5 pts
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So as you can see, AgNO3 is the limiting reagent, that means you can only make 0.265 grams of AgCl. For the next question, here you need to find moles of both of the Ca(NO3)2 solutions, so multiply their volumes (make sure its in Liters, not mL) by their molarities given. You will see that you have 0.0178 moles of the first solution, and 0.128 moles of the second. Add those two moles together, you will get 0.1458 moles total. Next add their volumes together (again makes sure its in Liters), you should get 0.1137 total Liters. The reason why we add moles and Liters together is because we are mixing those two solutions together. To find final concentration (Molarity), divide total number of moles by total number of Liters. Molarity = 0.1458 mol/0.1137 L. Molarity= 1.28 M Ca(NO3)2. Hope you find this helpful!

answered by @abbie • over 1 year ago