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A 10.0-mL solution of 0.0522 M AgNO3 was titrated with 0.0261 M NaBr in the following cell. S.C.E. || titration solution | Ag(s) Find the cell voltage for 0.1 and 30.5 mL of titrant. (Assume that the Nernst potential is 0.05916 V.) The answer isn’t (0.1=6.88) (30.5=0.0815)