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Calculate the standard reaction enthalpy for the reaction. CH4(g) + H2O(g) → CO(g) + 3H2(g) given 2H2(g) + CO(g) → CO(g) CH3OH(ℓ) ΔH° = -128.3 kJ • mol^-1 2CH4(g) + O2(g) → 2CH3OH(ℓ) ΔH° = -328.1 kJ • mol^-1 2H2(g) + O2(g) → 2H2O(g) ΔH° = -483.6 kJ • mol^-1 1. +216 kJ • mol^-1 2. +206.1 kJ • mol^-1 3. +412.1 kJ • mol^-1 4. +155.5 kJ • mol^-1 5. +42.0 kJ • mol^-1