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Question

An ideal gas is allowed to expand isothermally from 2.00 L at 5.00 atm in two steps; a) against a constant external pressure of 3.00 atm, followed by b) against a constant external pressure of 2.00 atm. Calculate q and w. (1.1.33 J = 1 L atm) 1. q = 743 J; w = -743 J. 2. q = 0 J; w = 0 J. 3. q = 125 J; w = -916 J. 4. q = 743 kJ; w = -743 kJ.



Comments
  • I think this answer is incorrect Julia N commented 12 months ago
  • The answer is incorrect. The correct answer is 4. For isothermal expension, the internal energy is zero, BUT q and w are not zeros. Anna commented 11 months ago
  • The correct answer is 1 because the numbers for answer 4 are correct but it is supposed to be in J not kJ Christian commented 11 months ago