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How many grams of CaCl2 are formed when 30.00 mL of 0.00237 M ca(OH)2 reacts with excess Cl2 gas? 2 Ca(OH)2(aq) + 2 Cl2(g) → Ca(OCl)2(aq) + CaCl2(s) + 2 H2O(l) a) 0.00395 b) 0.00789 g c) 0.0253 g d) 0.0158 g