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For the reaction, 8H2S(g) + 402(g) yields 8H20(g) + S8(g) The average rate of reaction during the time period from 30 s to 40 s is 1.42*10^-3 moles L^-1 s^-1. If the volume of the container is 3L, how many moles of O2 are consumed during this time period? a) 0.17 moles b) 0.043 moles c) 0.34 moles d) 0.057 moles e) 0.017 moles

  • The key I have for c117, says that the answer is a Marissa commented 6 months ago