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Focmaldehyt content in pesticides is determined by weighing 0.3124g of liquid samples into a 50,0ml bottle of NaOH0,0996M solution. and 50,0ml H2O23%. The reaction occurred as follows OH- + HCHO + H2O2 HCOO- + 2H2O After cooling, the residual base is titrated with 0.05250M H2SO4 solution to 23.3ml. What is the percentage of HCHO in the wine sample? (M = 30,026g / mol)