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Some CH2Cl2 is placed in a flask and heated to 412 K. When equilibrium is reached, the flask is found to contain CH2Cl2 (1.71x10^-2 M), CH4 (2.84x10^-2 M), and CCl4 (4.11x10^-2 M). What is the value of the equilibrium constant for the following at reaction at 412 K? 2CH2Cl2(g) ⇌ CH4(g) + CCl2(g)