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If a solution, made from 0.8 g of water and enough NaCl to yield a freezing point of -2.5, was added to excess lead (ll) nitrate solution, how many grams of precipitate would be expected? Please help me untangle this problem. I can see I need to determine the chemical equation, but the concentration of reactions (or colligative properties) and stoichiometry to find the limiting reactant is still abstract. Could you please help me work this out in a dimensional analysis format with canceling?