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Question

Given the following reactions: N2(g) + 2 O2(g) → 2 NO2(g) ΔH°r = +67.4 kJ/mol N2H4(l) + 3 O2(g) → 2 NO2(g) + 2 H2O(l) ΔH°r = -554.4 kJ/mol 2 H2(g) + O2(g) → 2 H2O(l) ΔH°r = -571.5 kJ/mol Calculate ΔH°f of N2H4(l), N2(g) + 2 H2(g) → N2H4(l)