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Determine the equilibrium constant for the following reaction at 498 K. 2 Hg(g) + O2(g) → 2 HgO(s) ΔH° = -304.2 kJ; ΔS° = -414.2 J/K a) 5.34 x 10^-11 b) 1.87 x 10^10 c) 2.31 x 10^-22 d) 8.10 x 10^31 e) 4.33 x 10^21