Ammonia (NH3, Kb = 1.8 x10-5) and trimethylamine [(CH3)3N, Kb = 7.4 x10-5] are weak bases. a. Which of these is the stronger base. Explain your reasoning. b. For the stronger base, calculate the pH and percent ionization of a 0.350 M solution.
You just have to look at the Kb values to know the stronger acid. A higher Kb value means that it is a stronger base. So, trimethylamine (CH3)3N will be the stronger base between the two.
The solution for pH and percent ionization is posted below. I hope this helps!