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KMnO4(aq) + 8HNO3(aq) + 5Fe(NO3)2(aq)  Mn(NO3)2(aq) + 5Fe(NO3)3(aq) + KNO3(aq) + 4H2O(l) A solution of Fe(NO3)2(aq) was formed by reacting the product from a thermite reaction in HNO3(aq). That solution was titrated with a 0.537 M solution of KMnO4(aq) according to the above equation, and it took 121 mL to convert all of the Fe2+ to Fe3+. How many moles of Fe2+ were contained in the original solution? So, based on your above answer, how many grams of iron were formed in the thermite reaction?