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A voltaic cell consists of an Mn/Mn^2+ half-cell and a Pb/Pb^2+ half-cell. Calculate {Mn^2+} when Ecell is 0.98 V and {Pb^2+} = 0.191 M. Use reduction potential values of Mn^2+ = -1.18 V and for Pb^2+ = -0.13 V.