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Copper(I) oxide can be oxidized to copper(II) oxide: Cu2O(s) + 1/2O2(g) ⟶ 2CuO(s) ΔH°rxn = −146.0 kJ Given ΔH°f of Cu2O(s) = −168.6 kJ/mol, find ΔH°f of CuO(s).