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Calculate the enthalpy of the reaction 4B(s) + 3O2(g) →2B2O3(s) given the following pertinent information: 1. B2O3(s) + 3H2O(g) → 3O2(g) + B2H6(g), ΔH°A = +2.35 kJ 2. 2B(s) + 3H2(g) → B2H6(g), ΔH°B = +36kJ 3. H2(g) + 1/2O2(g) → H2O(l), ΔH°C = -285kJ 4. H2O(l) → H2O(g), ΔH°D = +44kJ Express your answer numerically in kilojoules