Sucrose (ΔH°f = –2226.1 kJ/mol), or cane sugar, is a disaccharide of glucose (C6H12O6) and fructose (ΔH°f = –1265.6 kJ/mol). It is extremely abundant in the plant world.

asked by @student96818 • 9 months ago • Chemistry • 5 pts
  • Hey! What is your question about this? Dasha commented 9 months ago
  • OH, sorry. Calculate the enthalpy change for the hydrolysis reaction of sucrose. Sucrose+H2​O(l)=> C6​H12​O6​(s)+Fructose Sarah commented 9 months ago
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Hey there! Ok to solve this problem we need an equation.

△H rxn = △H f of products - △H f reactants.

△H rxn = [(1mole)(△Hf of C6H12O6)+ (1mole)(△Hf of Fructose)] - [(1mole)(△Hf of Sucrose) + (1mole)(△Hf of H2O)]

You will need to look up △Hf values for water and glucose (C6H12O6), since those were not given.

Note that we need to multiple △Hf values of each by the number of moles that appear in the balanced equation. Because we only have 1 mole of all the reactants and products, we only multiply by 1 mole here.

△Hf of water = -285.83 kJ/mol

△Hf of glucose = -1275.0 kJ/mol

Hope this helps you solve the problem.

answered by @dashab2 • 9 months ago