Hey there! Ok to solve this problem we need an equation.
△H rxn = △H f of products - △H f reactants.
△H rxn = [(1mole)(△Hf of C6H12O6)+ (1mole)(△Hf of Fructose)] - [(1mole)(△Hf of Sucrose) + (1mole)(△Hf of H2O)]
You will need to look up △Hf values for water and glucose (C6H12O6), since those were not given.
Note that we need to multiple △Hf values of each by the number of moles that appear in the balanced equation. Because we only have 1 mole of all the reactants and products, we only multiply by 1 mole here.
△Hf of water = -285.83 kJ/mol
△Hf of glucose = -1275.0 kJ/mol
Hope this helps you solve the problem.