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A chemist measures the enthalpy change ΔH during the following reaction: COCl2(g) + 4NH3(g) → CO(NH2)2(s) + 2NH4Cl(s) ΔH = 559. kJ Use this information to complete the table below. Round each of your answers to the nearest kJ/mol. 1/4CO(NH2)2(s) + 1/2(NH4Cl(s) → 1/4COCl2(g) + NH3(g)