A 2.5 g sample of a solid was completely vaporized in a 505 mL closed container at 428 K. If the measured pressure inside the container was 755 torr, what is the molecular weight of the solid?

asked by @davidam1 • 10 months ago • Chemistry • 5 pts
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1 answer

We will use the gas equation to solve this problem:

PV=nRT

n=PV/RT

We have to convert 755 torr to atm and 505 mL to L

(755 torr)(1atm/760torr)=0.99 atm

(505 mL)(1L/1000mL)=0.505 mL

n=PV/RT

n=((0.99atm)(0.505mL))/(0.0821)(428K)

n=0.014277 moles

n is equal to moles which is mass/molar mass

MM=mass/moles

MM= (2.5g/0.01428moles)

MM=175.106 g/mol

answered by @reyn • 9 months ago