What is the density (in g/L) of 1 mol of nitrogen gas (N2) at 375 K and 3.31 atm?

asked by @davidam1 • 10 months ago • Chemistry • 5 pts
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1 answer

Using the gas law,

PV=nRT

We can first calculate the volume

V=nRT/P

V=(1mol)(0.0821)(373K)/3.31 atm

V=9.2518 L

Nitrogen gas is N2 which has a molecular mass of 28.02 g/mol

Using this, we can now find the density using the given moles and the calculated volume

(28.02g/mol)(1 mol)(1/9.2518L)= 3.029 g/L

answered by @reyn • 10 months ago