You have a stock solution with a concentration of 309g/L you want to make one liter of solution with a concentration of 10 g/L
Hey @marias54! You can use a simple formula:
C1V1 = C2V2
C1 = Initial concentration
C2 = Final concentration
V1 = Initial volume
V2 = Final volume
The strategy is to find the minimum volume of initial concentration which can be diluted to 1 L in order to get required concentration.
309 (g/L) x V1 = 10 (g/L) x 1 L
V1 = 10/309 x 1 L = 0.03236 L x 1000mL/1L = 32.36 mL
This means that you need 32.36 mL of stock solution (309 g/L) and dilute it (with pure solvent like water etc) to 1000 mL (or 1L) and the resultant dilution will be of required concentration i.e. 10 g/L.