A rotating wheel requires 2.90-s to rotate through 37.0 revolutions. Its angular speed at the end of the 2.90-s interval is 98.2 rad/s. What is the constant angular acceleration of the wheel?

asked by @student11185 • 10 months ago • Physics • 5 pts
Add comment
1 answer

f=rev/s=37/2.9=12.76 s

wo=2pif=80.16 rad/s

wf=98.2 rad/s

a=(wf-wo)/2.9=(98.2-80.16)/2.9=6.22 rad/s^2

answered by @juanv2 • 10 months ago