Suppose a sample of acid had a measured pH of 1.21, calculate the concentration of the acid.

asked by @linhl13 • about 1 year ago • Chemistry • 5 pts
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1 answer

Hey there!

Assuming that the acid described in this problem is a strong monoprotic acid. The moles of the acid will just be equal to the concentration of {H+].

pH = -log[H+]

1.21 = -log[H+]

[H+]=10^(-1.21) = 0.0617 M

[H+]= [A] = 0.0617 M

I hope this helps!

answered by @leot1 • about 1 year ago