asked by @kaitlynm26 •
about 1 year ago •
Physics
• 5 pts

According to Kepler's Third Law of planetary motion, the ratio given here for the moon orbiting the Earth should be the same as a satellite. Therefore:

(19600)^3/T^2=1.01x10^18km^3/y^2

Solving for T we get .0027, which is in years. This converts to about 1 Earth day :)

answered by @juanv2 •
about 1 year ago

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