Calculate the heat produced when 250. mLs of 0.203 M Pb(NO3)2 is mixed with 250. mLs of 0.406 M NaBr. The initial temperature of both solutions before mixing is 24.25 ˚C. After mixing the final temperature of the mixture is 24.91 ˚C. Assume the specific heat of the solution is the same as the specific heat for water and the density of the solutions is the same as the density of water.

The precipitation reaction that forms lead(II) bromide is, Pb(NO3)2(aq) + 2NaBr(aq) ----> PbBr2(s) + 2NaNO3(aq)