The speed of a point on a rotating turntable, which is 0.156 m from the center, changes at a constant rate from rest to 0.528 m/s in 2.48 s. At t1 = 0.78 s, find the magnitude of its tangential accel

asked by @nikitavr1 • about 1 year ago • Physics • 5 pts
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1 answer

at=dv/dt

dv/dt=.528/2.48=.213 m/s^2

We are told we are accelerating at a constant rate, so a(.78)=.213 m/s^2

answered by @juanv2 • about 1 year ago