In this problem, we're going to use the kinematic expression for the range to get the take-off speed.

$\overline{){\mathbf{R}}{\mathbf{=}}\frac{{{\mathbf{v}}_{\mathbf{0}}}^{\mathbf{2}}\mathbf{s}\mathbf{i}\mathbf{n}\mathbf{2}\mathbf{\theta}}{\mathbf{g}}}$, where R is the range and g is the acceleration due to gravity.

We'll also use the kinematic equation:

$\overline{){\mathbf{\u2206}}{\mathbf{y}}{\mathbf{=}}{\mathbf{v}}{\mathbf{t}}{\mathbf{-}}\frac{\mathbf{1}}{\mathbf{2}}{\mathbf{g}}{{\mathbf{t}}}^{{\mathbf{2}}}}$

A long jumper leaves the ground at 45 above the horizontal and lands 9.1m away.

A. What is her "takeoff" speed v_{0} ?

B. Now she is out on a hike and comes to the left bank of a river. There is no bridge and the right bank is 10.0 m away horizontally and 2.5 m, vertically below. If she long jumps from the edge of the left bank at 45 with the speed calculated in A, how long, or short, of the opposite bank will she land?

C. Will she land on the opposite bank?

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Symmetrical Launch concept. You can view video lessons to learn Symmetrical Launch. Or if you need more Symmetrical Launch practice, you can also practice Symmetrical Launch practice problems.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Barwick's class at UCI.