Vertical Motion and Free Fall Video Lessons

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Problem: A 7550 kg rocket blasts off vertically from the launch pad with a constant upward acceleration of 2.30 m/s2 and feels no appreciable air resistance. When it has reached a height of 555 m, its engines suddenly fail so that the only force acting on it is now gravity.You may want to review (Pages 50 - 53).For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Up-and-down motion in free fall.a. What is the maximum height this rocket will reach above the launch pad?b. How much time after engine failure will elapse before the rocket comes crashing down to the launch pad?c. How fast will it be moving just before it crashes?

FREE Expert Solution

In this problem, we'll use the kinematic equations:

 vf = v0 +atx= v0t+12at2 vf2= v02 +2ax

The maximum height reached:

hmax=v022g

a.

The velocity of the rocket when teh engine fails can be found from the kinematic equation:

vf2 = v02 + 2aΔx

vf2-v02=2aHvf2-0=2aHvf=2aH=(2)(2.30)(555)

vf = 50.527 m/s

The motion between the interval 555 m and hmax:

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Problem Details
A 7550 kg rocket blasts off vertically from the launch pad with a constant upward acceleration of 2.30 m/s2 and feels no appreciable air resistance. When it has reached a height of 555 m, its engines suddenly fail so that the only force acting on it is now gravity.

You may want to review (Pages 50 - 53).

For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Up-and-down motion in free fall.

a. What is the maximum height this rocket will reach above the launch pad?

b. How much time after engine failure will elapse before the rocket comes crashing down to the launch pad?

c. How fast will it be moving just before it crashes?

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