Subjects

Sections | |||
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Intro to 2D Motion | 32 mins | 0 completed | Learn |

Projectile Motion | 67 mins | 0 completed | Learn |

More Projectile Motion | 42 mins | 0 completed | Learn |

Initial Velocity in Projectile Motion | 20 mins | 0 completed | Learn |

Circular Motion | 27 mins | 0 completed | Learn |

Additional Practice |
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Motion in 2D |

Motion in 2D & 3D With Calc |

Projectile Motion: Horizontal & Negative Launch |

Projectile Motion: Positive Launch |

Projectile Motion: Launch From Moving Vehicle |

Relative Motion |

Solution: The position of a squirrel running in a park is given by r = [(0.280 m/s)t + (0.0360 m/s 2)t2 ]i + (0.0190 m/s3 )t3 j.(a) What is vx(t), the xexttip{x}{x}-component of the velocity of the squirrel, a

The position of a squirrel running in a park is given by r = [(0.280 m/s)t + (0.0360 m/s ^{2})t^{2} ]i + (0.0190 m/s^{3} )t^{3} j.

(a) What is v_{x}(t), the xexttip{x}{x}-component of the velocity of the squirrel, as function of time?

(b) At 5.01 s, how far is the squirrel from its initial position?

(c) At 5.01 s, what is the magnitude of the squirrels velocity?

(d) What is v_{y}(t), the y-component of the velocity of the squirrel, as function of time?

(e) At 5.01 s, what is the direction (in degrees ccw from +x-axis) of the squirrels velocity?

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