Solution: A solid bar of length L has a mass m 1. The bar is fastened by a pivot at one end to a wall which is at an angle θ with respect to the horizontal. The bar is held horizontally by a vertical cord that is fastened to the bar at a distance x from the wall. A mass m2 is suspended from the free end of the bar. Find the tension in the cord. 1. T = (m1 + 1/2 m2) (L/x) gcosθ 2. T = (m1 + m2) gsinθ 3. T = (m1 + m2) gcosθ 4. T = (m1 + m2) (L/x) (g/2) 5. T = 0 6. T = (m1 + 1/2 m2) (L/x) g 7. T = (m1 + 1/2 m2) (L/x) gsinθ 8. T = (1/2 m1 + m2) (L/x) gsinθ 9. T = (1/2 m1 + m2) (L/x) g 10. T = (1/2 m1 + m2) (L/x) gcosθ