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Solution: A uniform rod of mass m and length l is pivoted about a hori...

Question

A uniform rod of mass m and length l is pivoted about a horizontal, frictionless pin at the end of a thin extension (of negligible mass) a distance l from the center of mass of the rod. The rod is released from rest at an angle of θ with the horizontal, as shown in the figure.

What is the magnitude of the Horizontal force Fx exerted on the pivot end of the rod extension at the instant the rod is in a horizontal position? The acceleration due to gravity is g and the moment of inertia of the rod about its center of mass is 1/12 mℓ2

1. Fx = 1/13 mg sin(θ)

2. Fx = 24/13 mg cos(θ)

3. Fx = 24/13 mg sin(θ)

4. Fx = 13/12 mg cos(θ)

5. Fx = 12/13 mg cos(θ)

6. Fx = 12/13 mg sin(θ)

7. Fx = 13/12 mg sin(θ)

8. Fx = mg cos(θ)

9. Fx = 1/13 mg cos(θ)

10. Fx = mg sin(θ)