Ch 13: Rotational EquilibriumWorksheetSee all chapters
All Chapters
Ch 01: Units & Vectors
Ch 02: 1D Motion (Kinematics)
Ch 03: 2D Motion (Projectile Motion)
Ch 04: Intro to Forces (Dynamics)
Ch 05: Friction, Inclines, Systems
Ch 06: Centripetal Forces & Gravitation
Ch 07: Work & Energy
Ch 08: Conservation of Energy
Ch 09: Momentum & Impulse
Ch 10: Rotational Kinematics
Ch 11: Rotational Inertia & Energy
Ch 12: Torque & Rotational Dynamics
Ch 13: Rotational Equilibrium
Ch 14: Angular Momentum
Ch 15: Periodic Motion (NEW)
Ch 15: Periodic Motion (Oscillations)
Ch 16: Waves & Sound
Ch 17: Fluid Mechanics
Ch 18: Heat and Temperature
Ch 19: Kinetic Theory of Ideal Gasses
Ch 20: The First Law of Thermodynamics
Ch 21: The Second Law of Thermodynamics
Ch 22: Electric Force & Field; Gauss' Law
Ch 23: Electric Potential
Ch 24: Capacitors & Dielectrics
Ch 25: Resistors & DC Circuits
Ch 26: Magnetic Fields and Forces
Ch 27: Sources of Magnetic Field
Ch 28: Induction and Inductance
Ch 29: Alternating Current
Ch 30: Electromagnetic Waves
Ch 31: Geometric Optics
Ch 32: Wave Optics
Ch 34: Special Relativity
Ch 35: Particle-Wave Duality
Ch 36: Atomic Structure
Ch 37: Nuclear Physics
Ch 38: Quantum Mechanics

Solution: A ball of radius r with a wire glued to one spot on its surface can be pulled along the floor and will slide without any tendency to roll only if the wire is horizontal and is a distance h above the floor. In terms of F, the magnitude of the applied force, fk, the magnitude of the force of kinetic friction, and the radius r of the ball, what is h? 1. h = r (f k − F) 2. h = 0; the wire must run along the floor. 3. h = r (f k/F) 4. h = r 5. h = r (1 + F/f k) 6. h = r (F − f k) 7. h = r (F/f k) 8. h = r (1 − f k/F) 9. h = r (1 + f k/F) 10. h = r (1 −F/f k)

Problem

A ball of radius r with a wire glued to one spot on its surface can be pulled along the floor and will slide without any tendency to roll only if the wire is horizontal and is a distance h above the floor. In terms of F, the magnitude of the applied force, fk, the magnitude of the force of kinetic friction, and the radius r of the ball, what is h?

1. h = r (f k − F)

2. h = 0; the wire must run along the floor.

3. h = r (f k/F)

4. h = r

5. h = r (1 + F/f k)

6. h = r (F − f k)

7. h = r (F/f k)

8. h = r (1 − f k/F)

9. h = r (1 + f k/F)

10. h = r (1 −F/f k)